IT subject - Wirless Access Technologies Please help to answers the following re
ID: 3604110 • Letter: I
Question
IT subject - Wirless Access Technologies
Please help to answers the following red circles questions by steps by steps as below :
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Q1 (a) Givent that center frequencies are 5 MHz apart between adjacent channels in 802.11g. (i)Channel 1 is between 2.401 GHz and 2.423 GHz. Determine the center frequencies of channel 3 and channel 11 respectively. Hence, calculate the separation between channel 3 and channel 11. [1 mark] [2 marks] (ii) (b) Complete the following table for a wireless LAN system. The values must be expressed in terms ofx, y and z. Data Rate ModulationCoding Number of Data Symbol Rate Bit/Symbol Mbit/s Msym/s BPSK PSK PSK x bit CCK x bit CCK bit Barker Code 1 4 [3 marks] (c) )The specifications of a wireless LAN system using Orthogonal Frequency Division Multiplexing (OFDM) are given as follows: Number of stream2 Number of data sub-carriers: 52 Channel bandwidth: 20 MHz Number of samples: 64 Guard Interval (GI): 0.6 s Modulation: 256 QAM Error coding Rate: 3/4 alculate: (i)) data symbol duration in us; (ii) signal duration in us; (iiii)) symbol rate in symbol/sec (iv)) number of data bits per OFDM symbol; (v)) data rate in Mbps. [2 marks] [2 marks] [2 marks] [2 marks] [2 marks]Explanation / Answer
import javax.swing.*;
import java.awt.*;
public class AlgorithmViewer {
public static void main(String[] args){
AlgorithmViewer av=new AlgorithmViewer();
}
public void Gui(){
JFrame frame=new JFrame();
JPanel panel=new JPanel();
JPanel panel2=new JPanel();
frame.setSize(800,800);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
final SelectionSortComponent component=new SelectionSortComponent();
final BubbleSortComponent component2=new BubbleSortComponent();
frame.add(panel);
frame.add(panel2);
panel.add(component);
panel2.add(component2);
frame.setVisible(true);
component.animation();
component2.animation();
}
public AlgorithmViewer(){
Gui();
}
}
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