IT subject - Wirless Access Technologies If you see the pictures not clear, plea
ID: 3604104 • Letter: I
Question
IT subject - Wirless Access Technologies
If you see the pictures not clear, please right click to download/save the picture in computer.
Please help to answers the following red circles for four questions by steps by steps as below :
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Q1 (a) Givent that center frequencies are 5 MHz apart between adjacent channels in 802.11g. 1) Channel 1 is between 2.401 GHz and 2.423 GHz. Determine the center frequencies of channel 3 and channel 11 respectively. [1 mark] (ii) ) Hence, calculate the separation between channel 3 and channel 11. [2 marks] (b) Complete the following table for a wireless LAN system. The values must be expressed in terms of x, y and z. Data Rate Modulation Coding Number of Data | Symbol Rate LMbit/s) Type BitSymbol (Msym/s) z BPSK Ty bit Barker Code 1 z QPSK tax bit CCK 4 (2 QPSK Tx bit CCK |8 t? I [3 marks] (C)) Briefly describe how Orthogonal Frequency Division Multiplexing (OFDM) deals with multipath propagation while maintaining high data rate. [4 marksExplanation / Answer
import javax.swing.*;
import java.awt.*;
public class AlgorithmViewer {
public static void main(String[] args){
AlgorithmViewer av=new AlgorithmViewer();
}
public void Gui(){
JFrame frame=new JFrame();
JPanel panel=new JPanel();
JPanel panel2=new JPanel();
frame.setSize(800,800);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
final SelectionSortComponent component=new SelectionSortComponent();
final BubbleSortComponent component2=new BubbleSortComponent();
frame.add(panel);
frame.add(panel2);
panel.add(component);
panel2.add(component2);
frame.setVisible(true);
component.animation();
component2.animation();
}
public AlgorithmViewer(){
Gui();
}
}
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