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Q1 Given the following FA defined over ={a,b,c}: Write down three strings accept

ID: 3609891 • Letter: Q

Question

Q1  

Given the following FA defined over ={a,b,c}:

Write down three strings accepted by this FA and threestrings rejected by it.

Q2    

2.1) Language L with Strings having“aba” anywhere in them

2.2) Language L with Strings, starting and endingwith “aba”

Write down the RE of following languages defined over = {a,b}:    

Q3    

Consider the language L, defined over = {a,b}, ofall non-empty strings having only “b” at odd clumps(however both “a” and “b” can occur at evenclumps, but the odd clumps should only be occupied by“b”)

i.e.

L = {b, ba, bb, bab, bbb, baba, babb, bbba, bbbb, babab, babbb,bababa, bababb, .…}

Q4  

Draw the FA for the language L defined over ={x,y} accepted by given RE:

(x+y)* (xx+yy) (x+y)*


Explanation / Answer

Dear.., 1)Three strings accepted by the above finite automata aac abc bac Three strings rejected by the above finite automata cac bcc bbb 2) Regular expression : Language L with Strings having “aba” anywhere inthem (a|b)*aba(a|b)* Language L with Strings, starting and ending with“aba” aba(a|b)*aba 3) Consider the language L, defined over = {a,b}, of allnon-empty strings having only “b” at odd clumps(however both “a” and “b” can occur at evenclumps, but the odd clumps should only be occupied by“b”) L= {b, ba, bb, bab, bbb, baba, babb, bbba, bbbb, babab, babbb,bababa, bababb, .…} Regular expression of this language:b|(b(a|b))* Means the above re generates L= {b, ba, bb, bab, bbb, baba, babb, bbba, bbbb, babab, babbb,bababa, bababb, .…} You try for last bit.. Still you have any doubts cramster isthere for you. I Hope this will helps you. 3) Consider the language L, defined over = {a,b}, of allnon-empty strings having only “b” at odd clumps(however both “a” and “b” can occur at evenclumps, but the odd clumps should only be occupied by“b”) L= {b, ba, bb, bab, bbb, baba, babb, bbba, bbbb, babab, babbb,bababa, bababb, .…} Regular expression of this language:b|(b(a|b))* Means the above re generates L= {b, ba, bb, bab, bbb, baba, babb, bbba, bbbb, babab, babbb,bababa, bababb, .…} You try for last bit.. Still you have any doubts cramster isthere for you. I Hope this will helps you. 3) Consider the language L, defined over = {a,b}, of allnon-empty strings having only “b” at odd clumps(however both “a” and “b” can occur at evenclumps, but the odd clumps should only be occupied by“b”) L= {b, ba, bb, bab, bbb, baba, babb, bbba, bbbb, babab, babbb,bababa, bababb, .…} Regular expression of this language:b|(b(a|b))* Means the above re generates L= {b, ba, bb, bab, bbb, baba, babb, bbba, bbbb, babab, babbb,bababa, bababb, .…} You try for last bit.. Still you have any doubts cramster isthere for you. I Hope this will helps you. Means the above re generates L= {b, ba, bb, bab, bbb, baba, babb, bbba, bbbb, babab, babbb,bababa, bababb, .…} You try for last bit.. Still you have any doubts cramster isthere for you. I Hope this will helps you.