Hi, I need a easier way to do a factorial program in c++ the program takes the i

Question

Hi, I need a easier way to do a factorial program in c++ the program takes the input from the command line (only onenumber) and the number should be a 8-bit unsigned integer,however the calculation should be in 32-bit signed integer and thenthe result is printed out . the output should be an integer with no ( e ) notation ; forexample 4e8 is not a valid output. if the calculation is impossible the programs gives a massege( " Impossible to calculate " ). please I need the codes with explainations . . . Hi, I need a easier way to do a factorial program in c++ the program takes the input from the command line (only onenumber) and the number should be a 8-bit unsigned integer,however the calculation should be in 32-bit signed integer and thenthe result is printed out . the output should be an integer with no ( e ) notation ; forexample 4e8 is not a valid output. if the calculation is impossible the programs gives a massege( " Impossible to calculate " ). please I need the codes with explainations . . .

Explanation / Answer

#include<iostream.h>

using namespace std;
int main(int argc, char * argv[])
{intnum;             
int factorial=1,i=1,previous=0;    //start factorialat multiplicative identity
                                  //previous is previous value of factorial
num =atoi(argv[1]);             //get character input from command prompt
                                    //and convert to integer
while(i<=num&&previous<=factorial)   //keepdoing it until find value you want or got overflow
  {previous=factorial;             //save factorial in previous, when next
   factorial*=i;                   //value is too big it will overflow and become negative
    i++;
    }
  
if(i==num+1)                        //when this occurs the value was found
cout<<num<<"! ="<<factorial<<endl;
else
cout<<num<<"! is impossible to calculate ";
   return 0;
}

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