What sequence of numbers would be printed by the followingrecursive procedure if

Question

What sequence of numbers would be printed by the followingrecursive procedure if we started it with N assigned the value1?

   procedure Exercise(N)
   print the value of N;
   if (n<3) then (apply the procedure Excersise to thevalue N+1);
   print the value of N.

The answer to this given is 1,2,3,3,2,1,..(can u please explain mewhy the numbers are given backwards?, is that because of the copiesthat return back the result to the original copy or somethingelse?

then after that is required what could be the termination conditionin the recursive procedure in the thing above.

Explanation / Answer

The numbers are printed back as the third line of the procedurealso has print the value of Nstatement. Now if the function is called with N=1, the overall fucntion callsand output will happen like this: Exercise(1): Prints (1) calls Exercise(1+1) ---------->                                            Prints(2)                                             calls Exercise(2+1)---------------------------->                                                                                                                    prints(3)                                                                                                                 N is not less than 3..no further Function call                                                                                                                  Prints(N which is 3 in this call)----|                                            Print(N..which is 2 in  

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