If x, y, and z are variables of type int with values4, 7, and 9 respectively, wh

Question

If x, y, and z are variables of type int with values4, 7, and 9 respectively, what is output by the following sequenceof printf() calls?     (Note: pleasewrite this C program in UNIX)              printf( "%d, %d, %d ", x + 2%x, ++z %x, y++ /x );              printf( "%d, %d, %d ", x + y + z++, 3*y/2, 3/2*y );              printf( "%d, %d, %d ", ++y + ++z, x - 4, 2 * x % 3 ); If x, y, and z are variables of type int with values4, 7, and 9 respectively, what is output by the following sequenceof printf() calls?     (Note: pleasewrite this C program in UNIX)              printf( "%d, %d, %d ", x + 2%x, ++z %x, y++ /x );              printf( "%d, %d, %d ", x + y + z++, 3*y/2, 3/2*y );              printf( "%d, %d, %d ", ++y + ++z, x - 4, 2 * x % 3 );              printf( "%d, %d, %d ", x + 2%x, ++z %x, y++ /x );              printf( "%d, %d, %d ", x + y + z++, 3*y/2, 3/2*y );              printf( "%d, %d, %d ", ++y + ++z, x - 4, 2 * x % 3 );

Explanation / Answer

If x, y, and z are variables of type int with values4, 7, and 9 respectively, what is output by the following sequenceof printf() calls?     (Note: pleasewrite this C program in UNIX)              printf( "%d, %d, %d ", x + 2%x, ++z %x, y++ /x );
                                    2%4=2, 4+2=6        9+1=1010%4 = 2    7/4=1  
                              at this point x=4, y=8, z=10
             printf( "%d, %d, %d ", x + y + z++, 3*y/2, 3/2*y );
                                          4+8+10=22     3*8=2424/2=12     3/2=11*8=8
                             at this point   x=4, y=8,z=11

             printf( "%d, %d, %d ", ++y + ++z, x - 4, 2 * x % 3 );
                                             9+12=21          4-4=0         2*4=8 8%3= 2
                                  at this point    x=4, y=9,z=12
The output  
             printf( "%d, %d, %d ", x + 2%x, ++z %x, y++ /x );
                                    2%4=2, 4+2=6        9+1=1010%4 = 2    7/4=1  
                              at this point x=4, y=8, z=10
             printf( "%d, %d, %d ", x + y + z++, 3*y/2, 3/2*y );
                                          4+8+10=22     3*8=2424/2=12     3/2=11*8=8
                             at this point   x=4, y=8,z=11

             printf( "%d, %d, %d ", ++y + ++z, x - 4, 2 * x % 3 );
                                             9+12=21          4-4=0         2*4=8 8%3= 2
                                  at this point    x=4, y=9,z=12
The output  

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