- DoNOT change anything in main() except for adding the one functioncall -hint:

Question

-          DoNOT change anything in main() except for adding the one functioncall

-hint: Use do-while and for loops.

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The tamplet:

//add generalprogram comments here



#include <iostream>
using namespace std;
int Function1(double []);
void PrintArray(const double [], int);

const int MAXSIZE =100;

int main()
{
   double array1[100];
   int count;

   count = Function1(array1);
   cout<<"There were "<<count<<"numbers entered into the array."<<endl;

   //function call to function that will print thearray


   return 0;
}

//Write the function here to read in numbers into the array. The array is called myarray.
//add comments describing what this function does, what is passedto it, what it sends back, etc.
int Function1(double myarray[])
{

}

//Write the new function here along with comments
//add comments describing what this function does, what is passedto it, what it sends back, etc.
void PrintArray(const double a1[], int size)
{

}

Explanation / Answer

please rate - thanks //add general program comments here #include using namespace std; int Function1(double []); void PrintArray(const double [], int); const int MAXSIZE =100; int main() {     double array1[100];     int count;     count = Function1(array1);     cout

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