Cij = sum(Aik*Bkj) This is matrixmultiplication. Written out long hand, it looks

Question

Cij = sum(Aik*Bkj)    This is matrixmultiplication. Written out long hand, it looks like this(I’m not using C++ array locations here – Ididn’t start with zero, I started with 1).

C11 = A11*B11 + A12*B21 +A13*B31        Array C is thenew array.

C21 = A21*B11 + A22*B21 + A23*B31      Array A is the (5X3) array.

C31 = A31*B11 + A32*B21 + A33*B31      Array B is the (3X1) array.

C41 = A41*B11 + A42*B21 + A43*B31

C51 = A51*B11 + A52*B21 + A53*B31

Test your program by filling the two dimensional array,row by row using loops, with the even numbers 2 through30. Fill the one dimensional array with the numbers 1, 2, and3. You can hard code these values into your program ratherthan use user input. Output each array as it looks (ie. The5X3 array should be printed as a 5X3, etc.)

Explanation / Answer

#include<iostream.h> #include<conio.h> #include<stdlib.h> using namespace std; int main() { int a[5][3],b[3][1],c[5][1]; short i,k; clrscr(); int count=2; for(i=0;i<5;i++) { for(k=0;k<3;k++) { a[i][k]=count; count++;    } } count=1; for(i=0;i<3;i++) { b[i][0]=count; count++; }
cout<<" Array A: "; for(i=0;i<5;i++) { cout<<" "; for(k=0;k<3;k++) {    cout<<a[i][k]<<""; } cout<<endl; }
cout<<" Array B: "; for(i=0;i<3;i++)    cout<<b[i][0]<<""; cout<<endl;

for(i=0;i<5;i++) { for(k=0;k<3;k++) { for(short v=0;v<1;v++) c[i][v]=c[i][k]+(a[i][v]*b[v][k]); } }
cout<<" Array c: "; for(i=0;i<5;i++) { cout<<" "; for(k=0;k<1;k++) {      cout<<c[i][k]<<" "; } cout<<endl; } system("pause); return 0; }
Hope you will find it helpfull

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