suppose the input is 3. what is the value of beta afterthe following c++ code ex
ID: 3616854 • Letter: S
Question
suppose the input is 3. what is the value of beta afterthe following c++ code executes: cin >> beta; switch (beta) { case 3: beta = beta + 3; case 1: beta ++; break; case 5: beta = beta + 5; case 4: beta = beta + 4; } I have no idea how this works. keep reading the book butit makes no sense. if i could get an explanation of what the"breaks" mean and what it means by "switch", it would begreat. then if i could get a run thru of what this code doeswith the input after each line it would be great suppose the input is 3. what is the value of beta afterthe following c++ code executes: cin >> beta; switch (beta) { case 3: beta = beta + 3; case 1: beta ++; break; case 5: beta = beta + 5; case 4: beta = beta + 4; } I have no idea how this works. keep reading the book butit makes no sense. if i could get an explanation of what the"breaks" mean and what it means by "switch", it would begreat. then if i could get a run thru of what this code doeswith the input after each line it would be greatExplanation / Answer
#include<iostream.h>
#include<conio.h>
int main()
{
int beta;
cout<<"Enter a Number in beta: ";
cin >> beta;
switch (beta) //suppose you provide 3 in beta
{
case 3: //condition true
beta = beta + 3; //now beta is 6
case 1: //now beta is 7
beta ++;
break; //exits from the switchstatement
case 5:
beta = beta + 5;
case 4:
beta = beta + 4;
}
cout<<"Beta Valueafter switch: "<<beta;
getch();
return 0;
}
#include<iostream>
using namespace std;
int main()
{
int beta;
cout<<"Enter a Number in beta: ";
cin >> beta; //supposeuser enter 3
switch (beta) //suppose you provide 3 in beta
{
case3: //conditiontrue
beta = beta +3; //nowbeta value is 6
case1: //nowbeta will enter in this case and become 7
beta ++;
break; //exitsfrom the switch statement, beta will not change in remainingcases
case 5:
beta = beta + 5;
case 4:
beta = beta + 4;
}
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