11 from Section 10.6 of Gilat Planck\'s radiation law gives the spectral radianc

Question

11 from Section 10.6 of Gilat

Planck's radiation law gives the spectral radiancy R as a function Of the wave length lambda. and temperature T (in degrees K): R = 2pic2h/lambda5 l/e(hc)(lambda KT) where c = 3.0 times 108 m/s is the speed of light, h = 6.63 times 10-34 J-s is the Planck constant, and k = 1.38 times 10-23J/K is the Boltzmann constant. Plot R as a function of lambda for 0.2 times 10-6 lambda 6.0 times 10-6 m at T = 1500K and determine the wavelength that gives the maximum R at this temperature.

Explanation / Answer

Here you go. I broke up the equation into two parts just so it was easier to keep track of c = 3E8; h = 6.63E-34; k = 1.38E-23; t =1500; lambda = [0.2E-6:.1E-6:6E-6]; part1 = 2*pi*c*c*h./lambda.^5 part2 = 1./(e.^(h*c./(lambda.*k.*t))) r = part1.*part2; plot(r) maximum = max(r)

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.