char str1[50] = \"don\'t judge a book by its cover\"; char str2[40] = \"book\";

Question

char str1[50] = "don't judge a book by its cover";
char str2[40] = "book";
Write a for loop with index i comparing 4 characters starting with str1+i to str2. Display the position in
str1 (that is index i) where a match is found.

//my code

#include <iostream>

using namespace std;

int findstr(char str[],char substr[]){

    int i,r;

    for(i=0;i<strlen(str);i++){

        r=strncmp(str+1, substr, strlen(substr));

        if(r==0)

            return (i);

    }

    return (-1);

}

int main(){

    char str[50] = "don't judge a book by its cover";

    char substr[20] = "book";

    int pos;

    pos=findstr(str, substr);

}

Explanation / Answer

please rate - thanks

change the 1 to i, I added some output

#include <iostream>

using namespace std;

int findstr(char str[],char substr[]){

    int i,r;

    for(i=0;i<strlen(str);i++){

         r=strncmp(str+i, substr, strlen(substr));

        if(r==0)

            return (i);

    }

    return (-1);

}

int main(){

    char str[50] = "don't judge a book by its cover";

    char substr[20] = "book";

    int pos;

    pos=findstr(str, substr);
    if(pos>0)
        cout<<substr<<" found at index "<<pos<<" of "<<str <<endl;
    else
        cout<<substr<<" not found in "<<str<<endl;

}

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