I was asked to: define integer list; ask the user to enter at least 5 numbers; t

Question

I was asked to: define integer list; ask the user to enter at least 5 numbers; to erase the middle number using c.erase(p). then display the element.

Here is my attempt

#include <iostream>
#include <list>
using namespace std;

int main ()
{

cout<<"Enter at least five integer Numbers" <<endl;
mylist<int> input_numbers;
unsigned int i;
list<unsigned int> mylist;

for (i=1; i<=5; i++) mylist.push_back(i);

mylist.erase (mylist.size()/2);

cout << "mylist contains:";
for (i=0; i<mylist.size(); i++)
cout << " " << mylist[i];
cout << endl;

return 0;
}

It did not work. Should I use while loop?

thank you

Explanation / Answer

Try this

--------------------------------------------------------

#include <iostream>
#include <list>
using namespace std;

int main ()
{

int l = 0;
unsigned int k = 0;
list<unsigned int> mylist;
list<unsigned int>::iterator it1,it2, it3;
bool Continue = true;


cout<<"Enter at least five integer Numbers enter (0) to stop: " << endl;
for (int j = 0; (Continue); j++) // I changed you read in method because i couldn't figure out how your were doing it
    {
    cout << "Integer " << (mylist.size () +1) << ": ";
    cin >> l;
    k = l;
   
    if (l == 0)
        if (j < 5)
            Continue = true;
        else
            Continue = false;
    else
        mylist.push_back (k);
    }

    it1 = mylist.begin ();
    for (int j = 0; j < (mylist.size ()/2); j++)
        {
        it1++; // I used the for loop to count the iterator up to the right spot
        }

    mylist.erase (it1);

    cout << "mylist contains:";
   
    int size = mylist.size ();
    for (int j = 0; j < size; j++)
        {
        cout << " " << mylist.front ();
        mylist.pop_front ();
        }
        cout << endl;

return 0;
}

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