In an input file each line has a students ID (4 digits), 4 test scores, and a fi

Question

In an input file each line has a students ID (4 digits), 4 test scores, and a final exam score. How do you write a program, in C++ using arrays and/or functions, that takes this input file, and calculates a grade. The grade is equal to 50% test average plus 50% final exam score. After it does this, the program creates an output file and on each line of the output file is the students ID, 4 test scores, final exam score, grade (3 decimal places), and a letter grade based on a 10 point grading scale.

Explanation / Answer

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#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;
char calculateGrade(double );
int main(){
int id,exam[4],final;
int i,sum;
char filename[80];
double grade;
ifstream in;
ofstream out;
cout<<"What is the name of your input data file? ";
cin>>filename;
   in.open(filename);           //open file
   if(in.fail())             //is it ok?
       { cout<<"input file did not open please check it ";
        system("pause");
        return 1;
        }
cout<<"What is the name of your output data file? ";
cin>>filename;
   out.open(filename);
   out<<"ID Exam1 Exam2 Exam3 Exam4 Final Average Grade ";       
in>>id ;                
   while(in)       
     {sum=0;
     for(i=0;i<4;i++)
          {in>>exam[i];
          sum+=exam[i];
          }
     in>>final;
     grade=sum/4.*.5+.5*final;
     out<<id;
     for(i=0;i<4;i++)
        out<<" "<<exam[i];
      out<<" "<<final<<" "<<setprecision(3)<<fixed<<grade<<" "
         <<calculateGrade(grade)<<endl;  
      in>>id;
      }
out.close();
in.close();
return 0;
}
char calculateGrade(double average)
{if(average >=90)
   return 'A';
else
   if(average >=80)
      return 'B';
    else
      if(average >=70)
            return 'C';
      else
         if(average >=60)
             return 'D';
         else
            return 'F';
}

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