In an instruction, how many bits need to be examined to determine the format of

Question

In an instruction, how many bits need to be examined to determine the format of an instruction? All 32 bits The first 6 bits The first hex digit The last 16 bits The following instruction is to be assembled and converted to binary target Assume that the current PC is 0x00400010 (after the increment) and the target label has the value of 0x00400080. What is the binary value of the constant in the instruction? 0000 0000 0111 0000 00 0001 0000 0000 0000 0010 0000 0000 0000 0001 1100 00 0100 0000 0000 0000 1000 0000 What is the following instruction? 0x00128882 srl 4 bits srl 2 bits sll 2 bits sll 4 bits

Explanation / Answer

Question 7. In an instruction, how many bits need to be examined to determine the format of an instruction?
To determine the format of an instruction in MIPS 6 bits has to be examined. The first 6 bits, from the left.
These bits are used to represent the opcode, i.e., the R-type of an instruction.
Therefore, the answer is: B. The first 6 bits.

Question 8. The following instruction is to be assembled and converted to binary.
j target
Assume that the current PC is 0x00400010 (after the increment), and the target label has the value of 0x00400080.
What is the binary value of the constant in the instruction?
This instruction can be written as: j 0x00400080.
Converting this instruction to binary, the instruction is: 00001000010000000000000010000000.
Here the first bits are for instruction, and therefore, the target(constant) is: 00010000000000000010000000.
Therefore, the answer is: D. 00 0100 0000 0000 0000 1000 0000

Question 9. What is the following instruction?
0x00128882
Converting this to binary will give: 00000000000100101000100010000010
This is a special instruction, and the division is:
000000   00000   10010   10001   00010   000010
Here, the last 6-bits represent the instruction SRL, and the format is: SRL rd, rt, sa [R-type]
Here, the shift bits is represented by the value sa. And it is 00010, which means 2 bits.
Therefore, the answer is: B. srl 2 bits.

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