So far I have this but certain inputs do not produce the right output. For examp
ID: 3630912 • Letter: S
Question
So far I have this but certain inputs do not produce the right output. For example, when I input 0101, the output is 65 instead of 5. When I input 1010 I get 3f2 instead of A. What should my final code look like?import java.util.Scanner;
import java.io.IOException;
public class YourProgram {
public static void main(String[] args) throws IOException{
//Create Scanner object
Scanner scan = new Scanner(System.in);
//Prompt
System.out.print("Enter an integer value: ");
int myInt = scan.nextInt();
//Convert
String retval = binaryToHex(
Integer.toBinaryString(myInt));
System.out.println("Hex value: " + retval);
}
public static String binaryToHex(String binaryValue) throws IOException{
long num = Long.parseLong(binaryValue);
long rem;
while(num > 0){
rem = num % 10;
num = num / 10;
if(rem != 0 && rem != 1){
System.out.println("This is not a binary number.");
System.out.println("Please try once again.");
System.exit(0);
}
}
int i= Integer.parseInt(binaryValue,2);
String hexString = Integer.toHexString(i);
return hexString;
}
}
Explanation / Answer
// working perfectly now
import java.util.Scanner;
import java.io.IOException;
public class YourProgram {
public static void main(String[] args) throws IOException{
//Create Scanner object
Scanner scan = new Scanner(System.in);
//Prompt
System.out.print("Enter an integer value: ");
String myInt = scan.next();
//Convert
String retval = binaryToHex(myInt);
System.out.println("Hex value: " + retval);
}
public static String binaryToHex(String binaryValue) throws IOException{
long num = Long.parseLong(binaryValue);
long rem;
while(num > 0){
rem = num % 10;
num = num / 10;
if(rem != 0 && rem != 1){
System.out.println("This is not a binary number.");
System.out.println("Please try once again.");
System.exit(0);
}
}
int i= Integer.parseInt(binaryValue,2);
String hexString = Integer.toHexString(i);
return hexString;
}
}
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