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<p>1. Converts the number to the basis set:<br /><br /> a. ( 1 1 0 1 1)<sub>2</s

ID: 3632042 • Letter: #

Question

<p>1. Converts the number to the basis set:<br /><br /> a. ( 1 1 0 1 1)<sub>2</sub> = ( &#191; ? )<sub>10</sub><br /><br /> b. ( 1 0 1 1 0)<sub>2</sub> = ( &#191; ? )<sub>10</sub><br /><br /> c. ( 1 0 1 1 1 1)<sub>2</sub> = ( &#191; ? )<sub>10</sub><br /><br /> e. ( 1 8)<span><sub>10</sub></span>&#160;= ( &#191; ? )<sub>2</sub></p>
<p><br /> f. ( 7 9)<sub>10</sub> = ( &#191; ? )<sub>2</sub><br /><br /> g. (1 0 1. 1 1)<sub>2</sub> = ( &#191; ? )<sub>10</sub></p>

Explanation / Answer

when we have a binary string, 11011 the first digit on the right has the coefficient of 2^0, next number is 2^1, etc... add the sum to find the answer in base 10 form. 2^0 + 2^1 + 2^3 + 2^4 = 1 + 2 + 8 + 16 = 27 when we have a integer 18 in base 10, we keep dividing the integer by two until the quotient is 0. note that r is the remainder. 18 /2 = 9 r = 0 9/2 = 4 r =1 4/2 = 2 r = 0 2/2 = 1 r = 0 1/2 = 0 r = 1 therefore, the answer is 10010 Ans a) 27 b) 22 c) 47 e) 10010 f) 1001111 g) 23

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