Hi, I\'ve been having trouble trying to figure out how to get my code to be able

Question

Hi,

I've been having trouble trying to figure out how to get my code to be able to determine if a string with a decimal value is a double. I'm required to use try/catch with Integer.parseInt and Double.parseDouble.

This is my program:

import java.io.*;
import java.util.Scanner;
//////////////////////////////////////////////////////////////////////////
class Assignment
{
//-----------------------------------------------------------------------------
public static void main (String [] args) throws Exception
{
while(true)
{
Scanner kb = new Scanner(System.in);
System.out.print("Enter a String: ");
String input = kb.nextLine();

try
{
Integer.parseInt(input);
System.out.println(input + " is an int.");
Double.parseDouble(input);
System.out.println(input + " is a double.");
}
catch(NumberFormatException e)
{
System.out.println();
}
}
}
//-----------------------------------------------------------------------------
} // end class Assignment
//////////////////////////////////////////////////////////////////////////

Trying to get the Output to look like this:

Enter a String: 9.8
9.8 is a double.

Any help would be greatly appreciated!

Explanation / Answer

import java.io.*; import java.util.Scanner; import java.lang.*; class Assignment { public static void main (String [] args) throws Exception { while(true) { Scanner kb = new Scanner(System.in); System.out.print("Enter a String: "); String input = kb.nextLine(); try { Integer.parseInt(input); System.out.println(input + " is a integer."); continue; } catch(NumberFormatException e) { System.out.println(); } try { Double.parseDouble(input); System.out.println(input + " is a double."); } catch(NumberFormatException e) { System.out.println(); } } } }

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