Hi, I\'m having trouble figuring out this problem. I don\'t know that ifthe rate

Question

Hi,

I'm having trouble figuring out this problem. I don't know that ifthe rate is affected proportional to the concentrations then itwould first order? I'm not sure. Please help!

The chemical reaction below gives the following experimentallydetermined results.
(CH3)3C–Cl + CH3CH2–OH--> (CH3)3C–O–CH2CH3 + H–Cl
t-butyl chloride    ethanol       ethyl t-butyl ether

1. Upon tripling the concentration of ethanol, the reaction rate istripled.
2. Upon halving the concentration of the t-butyl chloride, thereaction rate decreases by one-half.

Answer the following questions:
a) What is the kinetic order with respect to ethanol?
b) What is the kinetic order with respect of t-butyl chloride?
c) Write the rate equation for this reaction.
d) How would the rate be changed if we tripled the concentration ofthe t-butyl chloride while also doubling the concentration of theethanol.

Thanks!

Explanation / Answer

a) First order (the rate of reaction changes with concentration atequal magnitudes) b) First order c) Rate =k[CH3CH2OH][(CH3)3CCl] d) The rate would increase by a magnitude of five (the rate triplesas a result of tripling one reactant, while doubling as a result ofdoubling the other at the same time)

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