The simplest representation scheme is the BMP (bitmap), in which the image is re

Question

The simplest representation scheme is the BMP (bitmap), in which the image is represented as an mxn grid, with m rows, n columns, and therefore mn picture elements ("pixels"), plus a 56-byte (=448 bits) header. In this scheme, the color of each pixel is stored separately as a number with a fixed number of bits (usually either 8, 16, 24, or 32 bits). This is a quite space-intensive format! Representing each pixel with a k-bit number allows a selection of 2k distinct colors to appear in an image, but increases the storage requirements proportionately. For instance, the MCS Society logo (pictured below) measures 246 x 263, for a total of 64,698 pixels. A 16-bit BMP of this picture will therefore require 64698*16=1,035,168 bits to represent the grid, plus 56 additional bytes for the header, for a total of 1,035,616 bits.

Of course, your computer system will report the size of the image in bytes or kilobytes (or even megabytes or gigabytes), not bits. Recall that there are 8 bits in a byte, 1024 bytes in a kilobyte, 1024 kilobytes in a megabyte, 1024 megabytes in a gigabyte. Thus, a 16-bit BMP version of this image will require 129,452 bytes, or 126.418 kilobytes. (This is one reason why the BMP format is so seldom used -- the logo as shown on this web page is in PNG format, and occupies only 10.4 kilobytes of space.)

For this exercise, you are to write a program that will determine the amount of storage space needed for a BMP image with a given width and height (in pixels) and number of bits per pixel ("pixel depth"). You should output the amount in terms of bytes, kilobytes, and megabytes.

Example: (computer prompts in bold, user responses in italics):

Name of image: MCS_Society_logo_2005_16bit.bmp
width (in pixels): 246-user response
height (in pixels): 263-user response
Number of bits per pixel: 16-user response

The image 'MCS_Society_logo_2005_16bit.bmp'
will require 1035616 bits of storage to represent in BMP format,
which is 129452 bytes, or 126.418 KB, or 0.123455 MB.

Explanation / Answer

Since you did not specify the language that this program must be written in, I will answer it in C++. If you are using C or Java, the syntax will be slightly different. #include using namespace std; int main( int argc, char **argv ) { string image_file; int width, height, bpp; // bpp = bits per pixel cout > image_file; cout

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