Hi. assuming the hex value i want to split is A254 assuming the bits is 16 that

Question

Hi. assuming the hex value i want to split is A254

assuming the bits is 16

that means 4 will be seperated from A25 but I can't just use substring to split since the bits is a cin value and it could be different everytime i want to split a hex value.

How can i do this? thx

Explanation / Answer

sol: c++ how to split a hex value depending on bits consider ABCD(hex) is ur 16bit word. U like to split it into two 8 bit bytes.(high=AB(hex), low=CD(hex)) c++ how to split a hex value depending on bits we can do this by using AND operator (&). low=a&0x00FF is equivalent to a & 0000 0000 1111 1111; the higher bits are masked. just low=a wil also do, as low is char type(1 byte) and int being (2 byte) , type casting wil be done. c++ how to split a hex value depending on bits but still the concept is clear, use AND gate to mask. in case of high, high=a&0xFF00 wil result in a & 1111 1111 0000 0000. but we need the higher bits. Hence we use shift right operator (>>) moving it 8 times brings the higher 8 bit to lower 8 bit location. c++ how to split a hex value depending on bits eg. 1111 1111 0000 0000 >> 8 = 0000 0000 1111 1111 and %x in printf is to display data in hex. #include #include c++ how to split a hex value depending on bits void main() { unsigned int a=0xABCD; unsigned char low,high; low=a&0x00FF; high=(a>>8)&0x00FF; printf(" %x %x %x",a,high,low); getch(); } c++ how to split a hex value depending on bits

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