Homework: HW11 (Chapters 10 &11) Score: 3.43 of 4 pts 14 of 27 (27 complete) HUN

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Homework: HW11 (Chapters 10 &11) Score: 3.43 of 4 pts 14 of 27 (27 complete) HUN Score: 96.9%, 38.76 of 40 pts (%) Problem 10.28 Question Help Observation (minutes per cycle) Rating 125% 115% 90% 80% Element 35 13 34 37 Prepare daily reports Photocopy results Label and package reports Distribute reports 40 12 16 16 18 18 46A Photocopying machine broken; included as delay in the allowance factor A Power outage; included as delay in the allowance factor The allowance factor for this type of work is given to be 15%. Round all intermediate calculations to two decimal places before proceeding with further calculations. a) The normal time for the "prepare daily reports" operation 47.25 minutes (round your response to two decimal places). The normal time for the "photocopy results" operation = 14.95 minutes (round your response to two decimal places). The normal time for the "label and package reports" operation3.24 minutes (round your response to two decimal places) The normal time for the "distribute reports" operation = 14.8 minutes (round your response to two decimal places). The normal time for the overall process = 80.24 minutes (round your response to two decimal places). b) The standard time for this process = 94.4 minutes (round your response to two decimal places). c) The number of observations that are required for a 99% confidence level within 5% accuracy-370 (round your response to the immediate higher whole number Question is complete. Tap on the red indicators to see incorrect answers. All parts showing Similar Question

Explanation / Answer

Average time for Prepare daily report operations = (35+39+34+41+40)/ 5 = 189/5 = 37.8 minutes

Normal time for Prepare daily report operations =   Average time * Performance rating factor = 37.8 * 125% = 47.25 minutes

Average time for Photocopy result operations = (13+11+16+12)/ 4 = 52/4 = 13 minutes

Normal time for Photocopy result operations =   Average time * Performance rating factor = 13 * 115% = 14.95 minutes

Average time for Label and package reports operations = (2+3+5+5+3)/ 5 = 18/5 = 3.6 minutes

Normal time for Label and package reports operations =   Average time * Performance rating factor = 3.6 * 90% = 3.24 minutes

Average time for distribute reports operations = (16+18+22+18)/ 4 = 74/4 = 18.5 minutes

Normal time for distribute reports operations =   Average time * Performance rating factor = 18.5 * 80% = 14.8 minutes

Normal time for overall process = 47.25 + 14.95 + 3.24 + 14.8 = 80.24 minutes (difference because rounding to two decimal points)

Standard time for the process = Normal time / (1- allowance factor) = 80.24 / (1-15%) = 94.4 minutes

Required sample size = n = (z*s /h * x bar) ^2

Let’s first calculate for the first operation s = sqrt {sum (xi – x bar) ^2 / (n-1)}

= sqrt {(35 -37.8) ^2 + (39 – 37.8) ^2 + (34 – 37.8) ^2 + (41 – 37.8) ^2 + (40 – 37.8) ^2) / (5 -1)}

= sqrt {38.8/4} = sqrt (9.7) = 3.1145 minutes

Now Required sample size = n = (z*s /h * x bar) ^2

Where s = 3.1145 minutes

z at 99% confidence level = 2.576

h = 5% or 0.05

x bar = 37.8 minutes

Therefore n = (2.576 * 3.1145 / 0.05 * 37.8) ^2 = (4.25) ^2 = 18.02 = 18 observations

Repeat the above process for remaining three operations to calculate required sample size n for each. The sum of all the four operations will be 370 that is the number of observations required at 99% confidence level within 5% accuracy.

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