Could you please write this in JAVA... 12a, The median of an array is the elemen
ID: 3665197 • Letter: C
Question
Could you please write this in JAVA... 12a, The median of an array is the element m of the array such that half the remaining numbers in the array are greater than or equal to m and half are less than or equal to m, if the number of elements in the array is odd. If the number is even, the median is the average of the two elements m1, and m2 such that half the remaining elements are greater than or equal to m1 and m2, and half the elements are less than or equal to m1 and m2. Write a JAVA program that accept an array of numbers and returns the median of the number in the array.
Explanation / Answer
Assuming the array x is sorted and is of length n:
If n is odd then the median is x[(n-1)/2].
If n is even than the median is ( x[n/2] + x[(n/2)-1] ) / 2.
#include <stdio.h>
/* This function returns median of ar1[] and ar2[]. Assumptions in this function: Both ar1[] and ar2[] are sorted arrays Both have n elements */
int getMedian(int ar1[], int ar2[], int n)
{
int i = 0; /* Current index of i/p array ar1[] */
int j = 0; /* Current index of i/p array ar2[] */
int count;
int m1 = -1, m2 = -1;
/* Since there are 2n elements, median will be average of elements at index n-1 and n in the array obtained after
merging ar1 and ar2 */
for (count = 0; count <= n; count++)
{
/*Below is to handle case where all elements of ar1[] are smaller than smallest(or first) element of ar2[]*/
if (i == n)
{
m1 = m2;
m2 = ar2[0];
break;
}
/*Below is to handle case where all elements of ar2[] are smaller than smallest(or first) element of ar1[]*/
else if (j == n)
{
m1 = m2;
m2 = ar1[0];
break;
}
if (ar1[i] < ar2[j])
{
m1 = m2; /* Store the prev median */
m2 = ar1[i];
i++;
}
else
{
m1 = m2; /* Store the prev median */
m2 = ar2[j];
j++;
}
}
return (m1 + m2)/2;
}
/* Driver program to test above function */
int main()
{
int ar1[] = {1, 12, 15, 26, 38};
int ar2[] = {2, 13, 17, 30, 45};
int n1 = sizeof(ar1)/sizeof(ar1[0]);
int n2 = sizeof(ar2)/sizeof(ar2[0]);
if (n1 == n2)
printf("Median is %d", getMedian(ar1, ar2, n1));
else
printf("Doesn't work for arrays of unequal size");
getchar();
return 0;
}
check this one also
import java.applet.Applet;
import java.awt.Graphics;
import java.awt.*;
import java.awt.event.*;
public class whileloopq extends Applet implements ActionListener
{
Label label;
TextField input;
int num;
int index;
int[] numArray = new int[20];
int sum;
int total;
double avg;
int median;
public void init ()
{
label = new Label("Enter numbers");
input = new TextField(5);
add(label);
add(input);
input.addActionListener(this);
index = 0;
}
public void actionPerformed (ActionEvent ev)
{
int num = Integer.parseInt(input.getText());
numArray[index] = num;
index++;
if (index == 20)
input.setEnabled(false);
input.setText("");
sum = 0;
for (int i = 0; i < numArray.length; i++)
{
sum += numArray[i];
}
total = sum;
avg = total / index;
median = numArray[numArray.length/2];
repaint();
}
public void paint (Graphics graf)
{
graf.drawString("Total = " + Integer.toString(total), 25, 85);
graf.drawString("Average = " + Double.toString(avg), 25, 100);
graf.drawString("Median = " + Integer.toString(median), 25, 115);
}
}
formula is like this way
check this one also it may be helpful to you
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