Write a bash script that accepts one command line argument which is an integer b

Question

Write a bash script that accepts one command line argument which is an integer between 1 and 50. Output a list of integers as a result of iteratively applying a mathematical function f to the integer var. The function f is defined as f(x)=3x+1 if x is odd and f(x)=x/2 if x is even. Stop the iteration when the value 1 is reached. (Example: When var is 6, the play function’s output sequence should be 6,3,10,5,16,8,4,2,1.) Don’t call any external programs. Implement all algorithms in your script. You may choose whether to define a bash function or not in your script.

Explanation / Answer

!/bin/bash
echo -n "Enter a number between 1 and 50:"
read x
echo $x
while true
do
   if [ $x -eq 1 ]
   then
       break
   fi      
   if [ $(($x%2)) -eq 0 ]
   then
       x=$(( $x / 2 ))
       echo $x      
   else
       x=$(($x*3+1))
       echo $x
   fi      
done

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