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1. In a single server queue node, is it correct to obtain the following time ave

ID: 3680979 • Letter: 1

Question

1. In a single server queue node, is it correct to obtain the following time average statistics and why? Time average job in the node = 2.1, time averaged job number in the queue = 0.3, and time averaged job number in service = 1.2

2. In a simple inventory system, if you correctly obtained average demand as 92.3, how much is average order? 1. In a single server queue node, is it correct to obtain the following time average statistics and why? Time average job in the node = 2.1, time averaged job number in the queue = 0.3, and time averaged job number in service = 1.2

2. In a simple inventory system, if you correctly obtained average demand as 92.3, how much is average order? Time average job in the node = 2.1, time averaged job number in the queue = 0.3, and time averaged job number in service = 1.2

2. In a simple inventory system, if you correctly obtained average demand as 92.3, how much is average order?

Explanation / Answer

Answer for Question 1:
Formulae is to get the Time average job in the node is

L(t) = Q(t) + X(t)
where L is job in the node
Q is job number in the queue
X is job number in service
Based on the above Formulae
L(t) = 0.3 + 1.2 = 1.5

Answer for Question 2:

Given Average demand is 92.3
Average order is : Average demand / L(t) = 92.3/ 1.5 = 61.5