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What is the probability that Mark. Colleen. Jeff, and Emily win the first, secon

ID: 3687926 • Letter: W

Question

What is the probability that Mark. Colleen. Jeff, and Emily win the first, second, third, and fourth prizes, respectively, in a drawing if 30 people enter a contest and no one can win more than one prize. winning more than one prize is allowed. To roll a total of 8. do you prefer two dice or three dice Justify your answer. Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits arc independent and if a 0 bit and a 1 bit are equally likely. the probability that a bit is a 1 is 0.7. the probability that the ith bit is a 1 is 1/2^i for i = 1, 2, 3.........10. Find the probability that a randomly generated bit string of length 10 begins with a 1 or ends with a 00 for the same conditions as in parts (a), (b), and (c) of (i), if bits are generated independently. Assume that the probability a child is a girl is 0.6 and that the sexes of children bum into a family are independent. What is the probability that a family of four children has exactly three girls at least one boy at least one girl all children of the same sex Let X be the product of the numbers that appear when a pair of dice is rolled. What arc the values of this random variable for all the possible outcomes when these two dice are rolled Suppose that Lea selects a ball by first picking one of two boxes at random and then selecting a ball from this box. The first box contains 4 red balls and 6 purple balls, and the second box contains 8 red balls and 10 purple balls. What is the probability that Lea picked a ball from the second box if she has selected a red ball Suppose that 5% of the patients tested in a clinic are infected with avian influenza. Furthermore, suppose that w hen a blood test for avian influenza is given. 98% of the patients infected with avian influenza test positive and that 2% of the patients not infected with avian influenza test positive. What is the probability that

Explanation / Answer

Hi below i have given solution for two questions for your reference, Sorry i couldn;t get the exact solution for the rest.

2.To roll a total of 8 , do you prefer two dice or three dice?

n(s)= 6^3= 216 when we roll 3 dice .

now getting 8 on the three dice

6 1 1 these three numbers can be arranged in 3!/2! ways= 3ways
5 2 1 these three numbers can be arranged in 3! = 6ways
4 2 2 these three numbers can be arranged in 3!/2!= 3 ways
4 3 1 these three numbers can be arranged in 3!= 6 ways
3 3 2 these three numbers can be arranged in 3!/2!= 3 ways

total no of ways = 3+6+3+6+3= 21 ways

so desired probability = 21/216.

4. Assume that the probability a child is a girl is 0.6 and that the sexes of children born into a family are independent. What is the probability that a family of four children has

a) exactly three girls?

b) at least one boy?

c) at least one girl?

d) all children of the same sex?

a) P(a) = C(4, 3) * (0.6)^3 * (1-0.6)^4-3
b) P(b) = 1 - P(All girls) = 1 - (1-0.6)^4
c) P(c) = 1 - P(All boys) = 1 - 0.6^4
d) P(d) = P(All girls) + P(All boys) = (1-0.6)^4 + 0.6^4

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