Write a scheme function named double-list-elements that takes list as argument a

Question

Write a scheme function named double-list-elements that takes list as argument and returns a list that has a list with all elements doubled value. Write a scheme function double-list-elements-one that uses map function that takes the function and list as two inputs and produces the same output as the previous function Write your own version of map function do not use the predefined one.

Sample runs: (double-list-elements ‘(1 2 3)) should return (2 4 6)

(double-list-elements-one ‘(4 5)) should return (8 10)

Explanation / Answer

#Define the function double-list-element

def double-list-element ( a, b, c):

x=2*a;

y=2*b;

z=2*c;

mylist=[x,y,z];

return [mylist];

# Define the function double-list-elements-one

map(x):

return [2*x];

def double-list-element-one(map,a,b):

for i in 2

c=map(a);

d=map(b);

Newlist=[c,d];

print Newlist;

# Calling functions

arr=[1,2,3];

call_list=double-list-element(arr);

print call_list;

arr1=[4,5];

double-list-element-one(map,arr1);

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