1 int startingValue; 2 int terminatingValue; 3 int stepValue; 4 5 for (int i - s

Question

1 int startingValue; 2 int terminatingValue; 3 int stepValue; 4 5 for (int i - startingvalue; i terminatingValue; i + stepValue) switch( i ) 7 8 9 10 case e: System.out.print( "Hello there, ") break; 12 case 1: 13 14 15 16 17 18 19 20 21 System.out.println( "What's up? "); break; case 2: System.out.println( "How are you doing? ); break; case 3: System.out.printin "Terrific. ): break; case 4 System.out.printin( "Beautiful day isn't it? "; 23 24 25 26 27 28 29 / end switch 30 end for break; System.out-printIn( "Yes it is. ") System-out.println( "See you later case 5: break; default: Question 19

Explanation / Answer

The out put for the above programm is:

See you later.

See you later.

See you later.

what's up?

Explanation:

If you take the sequence of i values they are like...-5,-3,-1,1,3,5.....since starting value is -5 and it increments by step of 2. (-5+2=-3)....(-3+2=-1)..

But there is a condition in for loop that i should be less than or equal to terminatingValue (i<=1).

So for the above programm , the only valid values are -5,-3,-1,1

Note: Switch condition will execute the default case, when i value doesn't matches with any case number

For the i value =-5:

Since there is no case with -5, swich case will execute default case which prints See you later.

For the i value =-3:

Since there is no case with -3, swich case will execute default case which prints See you later.

For the i value =-1:

Since there is no case with -1, swich case will execute default case which prints See you later.

For the i value =1:

Since there exists a case with 1, So switch condition will execute case 1 which prints what's up?.

And the next value of i is 3 (1+2). But the condition is(i<=1). So the condition fails and the programm terminates.

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