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NAT TABLE 100% v Source IP 192.168.1.8 14356 192.168.1.9 14356 192.168.1.8 14356

ID: 3707801 • Letter: N

Question

NAT TABLE 100% v Source IP 192.168.1.8 14356 192.168.1.9 14356 192.168.1.8 14356 192.168.1.84500 Source Port Protocol TCP TCP UDP TCP Assigned Port Timestamp 1025 1026 1027 1027 1234567 1234523 1234562 1233456 Answer questions 1-3 referring to the NAT table above. In the questions below "incoming" packets refer to entering the network. "Outgoing packets leave the network. packets 1. An incoming packet is addressed to TCP port 1024. In response, the NAT should O Create a NAT entry Update time stamp in row 1 Ignore the packet Update time stamp in row 12 2. An incoming packet is addressed to TCP port 1027. In response, the NAT should Modify IP to 192.168.1.8, destination port to 4500 O Modify IP to 192.168.1.8, source port to 4500 Modify IP to 192.168.1.8, destination port to 4500, and update the Modify IP to 1921 68.1.8, source port to 4500, and update the timestamp 3. An outgoing UDP packet has source IP 192.168.1.3 and source port 12345. In response, the NAT should O change the IP to NATs public IP O create a new entry in the NAT table create a new entry in the NAT table, modify the source IP set source port to an assigned port O drop the packet 4. The IP address 221.1.3.4 is O a class A address O a class B address O a class C address a multicast address

Explanation / Answer

1. create a NAT entry

2. modify IP to 192.168.1.8, source port to 4500, and update the timestamp.

3.create a new entry in the NAT table, modify the source IP and set source port to an assigned port.

4. a class C address.