Take the height-balanced tree code, and replace the key field by a field int lea
ID: 3707854 • Letter: T
Question
Take the height-balanced tree code, and replace the key field by a field int leaves. That field should contain the number of leaves below the node, so n->leaves -1 if n is a leaf, and n->leaves-n->left->leaves + n->right->leaves else. The leaves field must be updated after an insertion or deletion for all nodes on the path from the root to the changed leaf, and after a rotation for the changed nodes Then vou (1) replace the find function by object.t *find_by_number (tree_node_t *tree, int k); which returns the object stored in the k-th leaf from left (start counting with the leftmost leaf as 1 (2) replace the insert function by void insert_by_number(tree-node-t *tree, int k, object.t *new_obj); which inserts new-obj in a new k-th leal, moving all leaves above it one step to the right (without renumbering), and (3) replace the delete function by object.t * delete_by_number (tree_node.t *tree, int k); which deletes (and returns) the object stored in the k-th leaf, moving all leaves above it one step to the left (without renumbering)Explanation / Answer
ANSWER:
HEIGHT BASE TREE CODE
#include <stdio.h>
#include <stdlib.h>
#define BLOCKSIZE 256
typedef int object_t;
typedef int key_t;
typedef struct tr_n_t { key_t key;
struct tr_n_t *left;
struct tr_n_t *right;
int height;
} tree_node_t;
tree_node_t *currentblock = NULL;
int size_left;
tree_node_t *free_list = NULL;
tree_node_t *get_node()
{ tree_node_t *tmp;
if( free_list != NULL )
{ tmp = free_list;
free_list = free_list -> left;
}
else
{ if( currentblock == NULL || size_left == 0)
{ currentblock =
(tree_node_t ) malloc( BLOCKSIZE sizeof(tree_node_t) );
size_left = BLOCKSIZE;
}
tmp = currentblock++;
size_left -= 1;
}
return( tmp );
}
2)this is second method of height based tree
#include<stdio.h>
#include<stdlib.h>
/* A binary tree node has data, pointer to left child
and a pointer to right child */
struct node
{
int data;
struct node* left;
struct node* right;
};
/* Compute the "maxDepth" of a tree -- the number of
nodes along the longest path from the root node
down to the farthest leaf node.*/
int maxDepth(struct node* node)
{
if (node==NULL)
return 0;
else
{
/ compute the depth of each subtree /
int lDepth = maxDepth(node->left);
int rDepth = maxDepth(node->right);
/ use the larger one /
if (lDepth > rDepth)
return(lDepth+1);
else return(rDepth+1);
}
}
/* Helper function that allocates a new node with the
given data and NULL left and right pointers. */
struct node* newNode(int data)
{
struct node node = (struct node)
malloc(sizeof(struct node));
node->data = data;
node->left = NULL;
node->right = NULL;
return(node);
}
int main()
{
struct node *root = newNode(1);
root->left = newNode(2);
root->right = newNode(3);
root->left->left = newNode(4);
root->left->right = newNode(5);
printf("Hight of tree is %d", maxDepth(root));
getchar();
return 0;
}
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