A 10 Mbps satellite channel is shared between 100 ground stations. All packets s
ID: 3718370 • Letter: A
Question
A 10 Mbps satellite channel is shared between 100 ground stations. All packets sent from ground stations to the satellite are 500 bytes long.
a) What is the maximum throughput of the channel if slotted ALOHA is used?
b) On an average, how many packets should each station transmit every second to realize the maximum throughput (if slotted ALOHA is used)?
c) What is the maximum throughput of the channel if plain ALOHA is used?
d) On an average, how many packets should each station transmit every second to realize the maximum throughput (if plain ALOHA is used)?
Explanation / Answer
Solution:
The slotted ALOHA maximum throughput formula is
S= G*e-G
Frame transmission time = 500 * 8/10 Mbps
= 40 * 10^-5 second =
G= 100 * 40 * 10^-5 * 2 = 8 * 10^-2
S= 8 * 10^-2 * e^-(8 * 10^-2) = 0.07384930771= 7.4 %
b)
Number of packets per slot = 0.14769861542frames per second
c)
The plain ALOHA maximum throughput formula is
S= G*e-2G
Frame transmission time = 500 * 8/10 Mbps
= 40 * 10^-5 second =
G= 100 * 40 * 10^-5 * 2 = 8 * 10^-2
S= 8 * 10^-2 * e^-(8 * 2 * 10^-2) = 0.06817150311= 6.8 %
d)
Number of packets per slot = 0.13634300623 frames per second
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