An application real-time uses the network depicted at Figure 2. The server sends
ID: 3718770 • Letter: A
Question
An application real-time uses the network depicted at Figure 2. The server sends a video to the client in real-time. To have a good quality of service (QoS), the client must receive 25 images per second. Suppose that an image is 10 Kbytes and UDP is used. The network can’t send a 10 Kbytes packet, so the image will be fragmented is smaller packets. The control information added to each packet is 100 bytes.
a. If the packet’s size is 1-Kbyte plus 100 bytes control information, is it possible for the server to send the video? Explain you answer.
b. If the packet’s size is 1-byte plus 100 bytes control information, is it possible for the server to send the video? Explain you answer.
R2 R3 10Mbps R1 100 Mbps 10 Mbps 100 Mbps Server ClientExplanation / Answer
a)
Absolutely, 1 Kbytes and 100 bytes will become 1100 bytes and in bits it will be 8800 bits
8800 bits is for one image
for 25 images 25*8800 = 220000 = 0.2 Mbps
which is very much possible to sent through the bottleneck of the network which is 10 Mbps
b)
Here there will be the overhead of control information because for every 1 byte 100 bytes of control information doesn't make sense,
10 for 10 Kbytes of an image we have to send 100*10 K 1M bytes of information
which means 8 M bits, for 1 image
and for 25 images it requires 25*8 = 200 Mbps not possible
I hope this helps if you find any problem. Please comment below. Don't forget to give a thumbs up if you liked it. :
a)
Absolutely, 1 Kbytes and 100 bytes will become 1100 bytes and in bits it will be 8800 bits
8800 bits is for one image
for 25 images 25*8800 = 220000 = 0.2 Mbps
which is very much possible to sent through the bottleneck of the network which is 10 Mbps
b)
Here there will be the overhead of control information because for every 1 byte 100 bytes of control information doesn't make sense,
10 for 10 Kbytes of an image we have to send 100*10 K 1M bytes of information
which means 8 M bits, for 1 image
and for 25 images it requires 25*8 = 200 Mbps not possible
I hope this helps if you find any problem. Please comment below. Don't forget to give a thumbs up if you liked it. :
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.