Can you write algorithm and comment for the fllowing python code. the form of al

Question

Can you write algorithm and comment for the fllowing python code. the form of algorithm and comment show in the picture. Thanks!

Code:

def deslang(slang, wordDictionary):

s=''

for i in slang.split(' '):

if i in wordDictionary:

i=wordDictionary[i]

s+=i+' '

return s[:-1]

  

def update_dictionary(file,dict):

try:

for i in open(file):

s=i.split(',')

dict[s[0]]=s[1]

print(file+" loaded successfully.")

except:

print(file+" does not exist.")

print("The dictionary has "+str(len(dict))+" entries.")

return dict

abgorithm: Prints Message based on iteration n 1. Take value n passed to the function 2. Iterate from 0 to n (inclusive) 3. For Each iteration n 4. if i is divisible by both 3 and 5, print FizzBuzz 5. if i is only divisible by 3, print Fizz 6. if i is only divisible by 5, print Buzz 7. else print the number Parameters n Returns: Nothing def fizz buzz(n): for i in range (e, n+1): # iterate from 0 to n inclusive # if i is 0, print 0 elíf í % 3 0 and ¡ % 5-0: # if 1 1s divisible by both 3 and 5 print FizzBuzz elif ? % 3-0: # if i is only divisible by 3, print Fizz elif í % 5- 0: # if I ls only divisible by 5, print Buzz print (0) print ('FizzBuzz')#output message print ('Fizz') print( 'Buzz') print(i) #output message #output message # else print number itself #output message #test case #test case else: fizz_buzz(5) fizz_buzz (15)

Explanation / Answer

def fizzbuzz(n):

if n % 3 == 0 and n % 5 == 0:

return 'FizzBuzz'

elif n % 3 == 0:

return 'Fizz'

elif n % 5 == 0:

return 'Buzz'

else:

return str(n)

print " ".join(fizzbuzz(n) for n in xrange(1, 21))

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.