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27.10 Loops*: Output integers as comma-separated list Given a list of integers,

ID: 3728105 • Letter: 2

Question

27.10 Loops*: Output integers as comma-separated list Given a list of integers, output those integers separated by a comma and space, except for the last which should be followed by a period (and newline). The first integers indicates how many integers are in the subsequent list. If the input is 41735, the output should be: 1,7,3, HINTS . Read in the first integer as numints, followed by a for loop that loops numints times . Decide whether to print the comma and space AFTER printing the current integer or BEFORE For each possibility, figure out how you'l handle the special cases of the first and last items, and then decide whether after or before is the best approach You can print the period and newline after the above for loop . ACTMETY 27.10.1:Loops* Output integers as comma-separated lis 0/6 main.cpp Load default template 2 using nonespoce std 6Type your code here 3 crnd

Explanation / Answer

Hello, below is the required code to print an input list as comma separated values, terminated by a period and a next line character. Comments are included, If you have any doubts, feel free to ask, Thanks

EDIT: Added another approach without using an array, added the code at the end.

//main.cpp

#include<iostream>

using namespace std;

int main(){

                //variable to store number of items

                int numItems;

                cout<<"Enter the input (number of items followed by items): ";

                //reading number of items

                cin>>numItems;

                //defining an array

                int list[numItems];

                //filling the array with remaining data

                for(int i=0;i<numItems;i++){

                                cin>>list[i];

                }

                cout<<"Output: "<<endl;

                //looping through all elements in the array

                for(int i=0;i<numItems;i++){

                                //printing the element

                                cout<<list[i];

                                if(i==numItems-1){

                                                //last element, printing a period and a next line char

                                                cout<<". ";

                                }else{

                                                //not the last element, printing a comma and a space

                                                cout<<", ";

                                }

                }

                return 0;

}

/*OUTPUT*/

Enter the input (number of items followed by items): 5 0 2 3 6 8

Output:

0, 2, 3, 6, 8.

Below is another approach without using an array, reading and printing elements on the go with one for loop.

//main.cpp

#include<iostream>

using namespace std;

int main(){

                //variable to store number of items

                int numItems;

                cout<<"Enter the input (number of items followed by items): ";

                //reading number of items

                cin>>numItems;

                int n;

                //getting the numbers, and printing it on the screen

                for(int i=0;i<numItems;i++){

                                //reading number

                                cin>>n;

                                //printing number

                                cout<<n;

                                if(i==numItems-1){

                                                //last element, printing a period and a next line char

                                                cout<<". ";

                                }else{

                                                //not the last element, printing a comma and a space

                                                cout<<", ";

                                }

                }

               

                return 0;

}

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