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In this part, you are asked to partition the Departmental network address block

ID: 3731319 • Letter: I

Question

In this part, you are asked to partition the Departmental network address block to create separate staff and student sub-networks. Your network must be able to support up to 51 machines on the staff network (not counting the router) and up to 337 machines on the student network (also not counting the router). You must choose the largest possible network address for the student network. You must then choose the smallest possible network address for the staff network. You must also choose the smallest possible size for the two sub-networks so that a visitor/guest network can be established in the future with the remaining network capacity.

Part 2A

Based on your partition, please answer the following questions that relate to the student network.

a. What is the network address of this network? [1 mark]

b. What is the network mask of this network? [1 mark]

c. What is the broadcast address in this network? [1 mark]

d. What is the lowest host IP address in this network? [1 mark]

e. Assuming that the router is assigned the largest available IP address in the range, what is the IP address of this network's router? [1 mark]

f. What is the largest host IP address in this network, excluding the router? [1 mark]

g. What is the maximum number of hosts that can be supported in this network? [1 mark]

Explanation / Answer

Solution:

We are considering class B for the given network which needs to be divided into subnetworks,

So the IP address is 192.168.1.32

The mask for this network is 255.255.0.0 this means that we have 2^16-2 hosts to divide.

for student network, we need only 51 machines and

This means that 6 bits are required for the address of this network

So, we will a lot 192.168.0.0 to 192.168.0.63

The mask for this address is 255.255.255.192

The staff subnetwork will be divided as

this means that 9 bits are requird to address this network

192.168.0.64-192.168.2.63

The mask will be 255.255.1.0

a)

What is the network address of this network?

The network address is: 192.168.0.0

b)

What is the network mask of this network?

255.255.1.0

c)

What is the broadcast address in this network?

192.168.0.63

d)

What is the lowest host IP address in this network?

192.168.0.1

e)

Assuming that the router is assigned the largest available IP address in the range, what is the IP address of this network's router?

192.168.254.0

f)

What is the largest host IP address in this network, excluding the router?

192.168.0.62

What is the maximum number of hosts that can be supported in this network?

2^9-2= 510, because 2 addresses for subnet id and the broadcast address.

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