3. (20 points) a. A host in an organization has an IP address of 158.78.118.108
ID: 3737161 • Letter: 3
Question
3. (20 points) a. A host in an organization has an IP address of 158.78.118.108 with a network mask of "/20" What is the network address of the subnet that this IP address belongs to? What is the range of the IP addresses that an individual host can have on this subnet? Justify your answers. A host in another organization has an IP address of 204.14.174.54 with a network mask of What is the network address of the supernet that this IP address belongs to? How many Class-C address blocks does this supernet include? Justify your answers. b. 20Explanation / Answer
3 ( a )
Address: 158.78.118.108 10011110.01001110.0111 0110.01101100
Netmask is /20
So the the netmask address would be as follows.
Netmask: 255.255.240.0 = 20 11111111.11111111.1111 0000.00000000 ( 20 MSB bits set to 1 )
The network address would be calculated as follows.
Address 158.78.118.108
Netmask 255.255.240.0
===========================
Network 158.78.112.0
Network: 158.78.112.0/20 10011110.01001110.0111 0000.00000000 (Class B range 128 - 191)
Broadcast: 158.78.127.255 10011110.01001110.0111 1111.11111111
The range of host will be as follows.
The minimum host will the next host address from the network address.
The maximum host will the previous host address of the Broadcast address.
HostMin: 158.78.112.1 10011110.01001110.0111 0000.00000001
HostMax: 158.78.127.254 10011110.01001110.0111 1111.11111110
Total Hosts/Net: 2 ^ 12 = 4096 - 2 = 4094
Total hosts = (2 to the power of no. of host bits) - 2
Total hosts is subtracted by 2 as the network address and broadcast address of the subnet cannot be used by any other hosts. So these two are not included in total hosts range.
3 (b)
Address: 204.14.174.54 11001100.00001110.1010 1110.00110110
Netmask is /20
So the the netmask address would be as follows.
Netmask: 255.255.240.0 = 20 11111111.11111111.1111 0000.00000000 ( 20 MSB bits set to 1 )
The network address would be calculated as follows.
Address 204.14.174.54
Netmask 255.255.240.0
=============================
Network 204.14.160.0
Network: 204.14.160.0/20 11001100.00001110.1010 0000.00000000 (Class C Range = 192 – 223 )
Broadcast: 204.14.175.255 11001100.00001110.1010 1111.11111111
The range of host will be as follows.
The minimum host will the next host address from the network address.
The maximum host will the previous host address of the Broadcast address.
HostMin: 204.14.160.1 11001100.00001110.1010 0000.00000001
HostMax: 204.14.175.254 11001100.00001110.1010 1111.11111110
Total Hosts/Net: (2 ^ 12) - 2 = 4096 - 2 = 4094
Total hosts = (2 to the power of no. of host bits) - 2
Total hosts is subtracted by 2 as the network address and broadcast address of the supernet cannot be used by any other hosts. So these two are not included in total hosts range.
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