Please help with #4 and if needed #3. 3. Let us consider a computer that has a b
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Please help with #4 and if needed #3.
3. Let us consider a computer that has a byte-addressable memory organized in 32-bit words according to the big-endian scheme. A program reads ASCII characters entered at a keyboard and stores them in successive byte locations, starting at location 1000. Show the contents of the two memory words at locations 1000 and 1004 after the word "BuckeyesColumbus" has been entered. Give the contents for the two words irn hexadecimal. Repeat the problem for the little-endian scheme. (l6pts, 4pts each) Repeat Problem #3 for word-addressable memory organized in 16-bit words, for both big- endian and little-endian. (l6pts, 4pts each) 4.Explanation / Answer
The computer that has a byte-addressable memory organized in 32-bit words according to the big-endian scheme. A program reads ASCII characters entered at a keyboard and stores them in successive byte locations, starting at location 1000. Show the contents of the two memory words at locations 1000 and 1004 after the word “BuckeyesColumbus” has been entered.
Byte contents in hex starting at location 1000 will be 42, 75, 63, 6B, 65, 79, 65, 73, 43, 6F, 6C, 6F, 6D, 62, 75, 73.
The two words at 1000 and 1004 will be (for big-endian ) 42 75 63 6B and 65 79 65 73
The two words at 1000 and 1004 will be (for little-endian ) 6B 63 75 42 and 73 65 79 65
4. Here, word-addressable memory organized in 16 - bit (2- byte) words, therefore aligned words begin at byte addresses 0, 2, 4,.....
Byte contents in hex starting at location 1000 will be 42, 75, 63, 6B, 65, 79, 65, 73, 43, 6F, 6C, 6F, 6D, 62, 75, 73.
The two words at 1000 and 1004 will be (for big-endian ) 42 75 and 65 79
The two words at 1000 and 1004 will be (for little-endian ) 75 42 and 79 65
Character B u c k e y e s C o l o m b u s Hexadecimal equivalent 42 75 63 6B 65 79 65 73 43 6F 6C 6F 6D 62 75 73Related Questions
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