Assume that the nodal processing delay is negligible. Also, assume that the link

Question

Assume that the nodal processing delay is negligible. Also, assume that the link between A and the router is 10,000 meters long and the link between B and the router is 20,000 meters long. If the propagation speed in both links is 200,000,000 m/sec, answer the following questions:

a. What is the end-to-end network throughput when a 100KB file is transferred from B to A? Assume that the router's buffer is large enough to avoid any data loss possibilities. Also, assume that the file is divided into 50 2KB chunks by B before being transferred to A and the router forwards a data chunk to A when it completely receives it from B

b. Assume that B sends a 2GB (234 bits) file to A after chunking it to 2KB packets. What should be the minimum router buffer size if we want to avoid any data loss for this file transfer?

Explanation / Answer

a) Propagation time from B to router = d/v = 20000/200000000 = 10-4

Propagation time from router to A = d/v = 10000/200000000 = 5*10-5

Propagation time from B to A = d/v = 30000/200000000 = 1.5*10-6

nodal processing delay is negligible so Propagation time from B to A = 10-4 + 5*10-5 =  1.5*10-6

throughput = bandwidth * efficiency

efficiency = 1

throughput = bandwidth

b)  nodal processing delay is negligible so we need only two buffer because at the time one chunk is received another packet has arrived and also not transmitted the first packet so we need the second buffer to store the second packet.and when the first packet is transmitted and second is received at that time third arrives so it will store at first packet vacant buffer.

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