Problem: Write a program in C that will calculate the salary raise for employees

Question

Problem: Write a program in C that will calculate the salary raise for employees as follows:

if salary is between $0 < $30000 the rate is 7.0%

if salary is between $30000 <= $40000 the rate is 5.5%

if salary is more than $40000 the rate is 4.0%

Instructions Given:

1. Use the appropriate functions and pass parameters for this program. Include at least one function that uses the return statement (non-void) and at least one

function that does NOT use the return statement (void).

2. Write a function that allows user to input the salaries (as many as they want) using a loop (only while, do, or for loops allowed).

3. Write a function that calculates the raises, the new salaries (raise + salaries), the total of the original salaries, the total of raises and the total of all the new salaries with the raises.

4. Write a function to print the output formatted like the in the following example (please do not add anything other than the ones listed)

5. You may have more functions than the 3 listed above

6. Loops and simple if/ if else statments allowed. You may either use a while loop, do loop, or for loops. DO NOT USE structs, arrays, etc.

7. Do not include other header files other than stdio.h and stdlib.h

Salary Rate % Raise New Salary 0.00 25,000.00 30,000.00 35,000.00 40,000.00 40,001.00 45,000.00 $215,001.00 0.00 0.00 0.00 7.00 1,750.00 26,750.00 5.50 1,650.00 31,650.00 5.50 1,925.00 36,925.00 5.50 2,200.00 42,200.00 4.00 1,600.04 41,601.00 4.00 1,800.00 46,800.00 $10,925.04 $225,926.00 Total

Explanation / Answer

Answer:

int main() {
    float basic;
    float rate1=7.0;
   float rate2=5.5;
   float rate3=4.0;
   float hike1,hike2,hike3;
   float new_salary;

   int ch=9;
  
   switch(ch)
   {
   printf("Enter 0 to quit and any other number to proceed");
   case 0:
   exit(0);
   break;
  
   default:
  
printf("Enter basic salary of employee : ");
scanf("%d", &basic);
  
   if(basic<=30000)
   hike1= (rate1 * basic) / 100;
   new_salary = basic + hike1;
   else if(basic>30000 && basic<=40000)
   hike2= (rate2 * basic) / 100;
   new_salary = basic + hike2;
   else
   hike3= (rate3 * basic) / 100;
   new_salary = basic + hike3;

printf(" The new salary is %f $",new_salary);
  
   break;
  
  


return (0);
}

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