Complete this partially written Java program that reverses the order of five num

Question

Complete this partially written Java program that reverses the order of five numbers stored in an array. First the program should print the 5 numbers then pass the array to a method where the numbers are reversed and finally the program should print the reversed numbers.

// Reverse.java - This program reverses numbers stored in an array.
// Input: Interactive.
// Output: Original contents of array and the reversed contents of the array.

import javax.swing.*;

public class Reverse
{
   public static void main(String args[])
   {
       int numbers[] = {9, 8, 7, 6, 5};
       int x;

       // Print contents of array
      
      
       // Call reverseArray method here      
      
  
       // Print contents of reversed array
      
      
       System.exit(0);

   } // End of main() method.
  
  
   // Write reverseArray method here.
  

} // End of Reverse class.

Explanation / Answer

Here is the code for you. If you need any further refinements, just get back to me.

// Reverse.java - This program reverses numbers stored in an array.
// Input: Interactive.
// Output: Original contents of array and the reversed contents of the array.
import javax.swing.*;
public class Reverse
{
public static void main(String args[])
{
int numbers[] = {9, 8, 7, 6, 5};
int x;
// Print contents of array
display(numbers);
  
  
// Call reverseArray method here
reverseArray(numbers);
  
  
// Print contents of reversed array
display(numbers);
  
  
System.exit(0);
} // End of main() method.
  
  
// Write reverseArray method here.
public static void reverseArray(int numbers[])
{
for(int i=0;i<numbers.length / 2;i++)
        {
        int temp = numbers[numbers.length-i-1];
        numbers[numbers.length-i-1] = numbers[i];
        numbers[i] = temp;
        }
}

public static void display(int numbers[])
{
for(int i = 0; i < numbers.length; i++)
System.out.print(numbers[i]+" ");
System.out.println();
}
  
} // End of Reverse class.

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