5. Show the output of each of the following C++ program segments: int j; int one

Question

5. Show the output of each of the following C++ program segments:

int j;

int one[5], two[10];

for (j = 0; j < 5; j++)

    one[j] = 5*j + 3;

cout << “One cntains: “;

for (j = 0; j < 5; j++)

     cout << setw(3) << one[j];

cout << endl;

for (j = 0; j < 5; j++)

{    two[j] = 2*one[j] - 1;

      two[j + 5] = one[4 - j] – 1 + two [j];

}

cout << “Two cntains: “;

for (j = 0; j < 10; j++)

     cout << setw(3) << two[j];

cout << endl;   

**********************************************************************************

const int n = 6;

int L[n] = {3, 5, 5, 4, 9, 9};

bool valu = true;

int k = 0;

while ( (k <n-1) && (valu) )

{

    if (L[k] > L[k+1])

       {

          valu = false;

          cout << setw(2) << k << setw(2) <<L[k] << endl;

       }

    else

          k++;    

}

if (valu)

            cout << “ The list is OK” << endl;

Explanation / Answer

SEGMENT 1:

Output:

One cntains: 3 8 13 18 23
Two cntains: 5 15 25 35 45 27 32 37 42 47

SEGMENT 2:

Output:

Try this code:

segment 1:

#include <iostream>
#include <iomanip>

using namespace std;

int main() {
int j;
int one[5], two[10];
for (j = 0; j < 5; j++)
one[j] = 5*j + 3;
cout << "One cntains:";
for (j = 0; j < 5; j++)
cout << setw(3) << one[j];
cout << endl;

for (j = 0; j < 5; j++)
{
two[j]=2*one[j]-1;
two[j+5] = one[4-j] - 1 + two[j];
  
}
cout << "Two cntains:";
for (j = 0; j < 10; j++)
cout << setw(3) << two[j];
cout << endl;   
return 0;
}

segment 2:

#include <iostream>
#include <iomanip>
using namespace std;

int main() {
   const int n = 6;
int L[n] = {3, 5, 5, 4, 9, 9};
bool valu = true;
int k=0;
while ( (k <n-1) && (valu) )
{
if (L[k] > L[k+1])
{
valu = false;
cout << setw(2) << k << setw(2) <<L[k] << endl;
}
else
k++;
}
if (valu)
cout << "The list is OK" << endl;
   return 0;
}

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