A converts analog to digital at a = 59 Kbps Link transmission rate R = 4.2 Mbps

Question

A converts analog to digital at a = 59 Kbps Link transmission rate R = 4.2 Mbps Host A groups data into packets of length L = 116 bytes Distance to travel d = 871.8 km Propagation speed s = 2.5 x 108 m/s Host A sends each packet to Host B as soon as it gathers a whole packet. Host B converts back from digital to analog as soon as it receives a whole packet. How much time elapses from when the first bit starts to be created until the conversion back to analog begins? The answer is 19.44ms but I don't understand how they got this number.

Explanation / Answer

1 byte = 8 bits.
Packet Length in bits => 116 x8 = 928 bits.

To generate a packet it will take : (928)/ (59) = 15.72 ms [Note the unit ms ] .
Link Transmission rate = 4.2 x 106 sec = 4.2 x 103 ms (Given)
To transmit the packet of 928 bits it will take : 928/ (4.2 x 103 ) = 0.22 ms.
Time To travel a distance of 871.8 km at propagation speed of 2.5 x 108  ms : => 871.8 x 103 m / (2.5 x 108 )
=> 3.48 ms.

Time elapses from when the first bit starts to be created until the conversion back to analog begins =>
15.72 + 0.22 + 3.48 =~ 19.44 ms.


Thanks, I hope it clarifies. Let me know if there is anything.

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