Assignment Alloy Cost Analysis Due (with no exceptions) on Jan 2017 Aluminum alo

Question

Assignment Alloy Cost Analysis Due (with no exceptions) on Jan 2017 Aluminum aloys are made by adding other elements to aluminum to improve its propertes, such as hardnessc tensile strength. The folowing table shows the composton offive commonly used aloys, which are known by ther alloy numbers (2024,6061, and so on) Kutz, 1999). Composition of aluminum alloys 1005 03 0 The cost of each element per unitamount is shown in the folowing table Material cost ofeach element per ton 45 The manufacture cost for each type of aloyalsoindudes costs orlabour and transportaton,inaddson aluminum tothe material cost, as showninthe following table: Unit Product costs s x 10l per ton) Labour Transportation Calculated based on abovetaties Calculatedbased on above tables 7005 Calaulated based on abovetables 7075 based on abovetables 5 Calculated based on above abies The following tableshows the production volume ofeach productforthe four quaners of the business year Quarterly production volume Quarter 1 Quarter 2 Quarter3 Quarter 4

Explanation / Answer

Code:

comp = [93.5 4.4 1.5 0.6 0 0;
        96.4 0 1 0 0.6 0;
        94.1 0 1.4 0 0 4.5;
        90.3 1.6 2.5 0 0 5.6;
        92.7 0 0.3 0 7 0];
cost = [2.0 7.1 2.65 4.5 3.2 2.1];
qprod = [16 14 10 12;
          12 15 11 13;
          8 9 7 11;
          14 13 15 17;
          13 16 12 18];
labour = [3 1 4 5 2];
transport = [2 3 5 4 1];
each_cost = [];
for i=1:5
   for j=1:6
       each_cost(i,j) = comp(i,j)/100*cost(j);
   end
end  
alloy_cost = [];
for i=1:5
   alloy_cost(i)=sum(each_cost(i:i,1:6));
end  
tot_cost = [];
for i=1:5
    tot_cost(i) = alloy_cost(i)*sum(qprod(i));
end  
labour_cost = [];
for i=1:5
    labour_cost(i) = sum(qprod(i))*labour(i);
end
trans_cost = [];
for i=1:5
    trans_cost(i) = sum(qprod(i))*transport(i);
end
fprintf('Total Material cost is $ %.2f ',sum(tot_cost));
fprintf('Total Labout cost is $ %.2f ',sum(labour_cost));
fprintf('Total Transportation cost is $ %.2f ',sum(trans_cost));

Output:

Total Material cost is $ 132.35
Total Labout cost is $ 188.00
Total Transportation cost is $ 177.00

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