In a Pc using an Intel 8085 microprocessor, the number of bits in a hex digit is

Question

In a Pc using an Intel 8085 microprocessor, the number of bits in a hex digit is bits in a doubleword is bytes in a word is. hex digits in a doubleword is Suppose that a word contains EC F9 12 Given that this word represents an unsigned decimal number, what is the decimal Given that this word is a 2's complement representation for a signed decimal number. what is the decimal number? Give the 2's complement of FFC8 Perform each of the following additions of word size numbers. Give the sum in hex as a word size number. State whether or not overflow occurs. State whether or not there is a carry. Check each answer by converting the problem to both decimal interpretations (unsigned and 2's complement); show that the unsigned interpretation is correct when there is no carry, and the signed interpretation is correct when there is no overflow. FFFA + 03B1 FFFA + FFFB

Explanation / Answer

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1)

a) bits in a hex digit is 4

b)bits in a doubleword is 32 bits

c)bytes in a word is 2 bytes

d)hex digits in doubleword is 8 hex digits

2)Given ,Word = EC F9 = 1110 1100 1111 1001

a) If word represents a unsigned decimal number then the number is

1*20+1*23+1*24+1*25+1*26+1*27+1*210+1*211+1*213+1*214+1*215 = 60,665

b)if word represents a signed decimal number then the number is

1*20+1*23+1*24+1*25+1*26+1*27+1*210+1*211+1*213+1*214 - 1*215 = -(4,871) (negative number)

c)Number is FF CB = 1111 1111 1100 1011

1's complement = 0000 0000 0011 0100

2's complement = 1's complement + 1

(0000 0000 0011 0100)2 + (1)2 = (0000 0000 0011 0101)2 = 00 35

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