Can someone help me with this program... in Java, please. Prompt the user to ent

Question

Can someone help me with this program... in Java, please. Prompt the user to enter a string containing a hexadecimal number. Use class Integer to parse the input to a base-10 integer variable and display it. Convert this base-10 variable to a string holding an equivalent number in binary. Print this binary equivalent. Use class Integer to convert the binary string back to base-10 and display it. SAMPLE OUTPUT Enter a string holding a hexadecimal integer less than 256 1a That hex number in base-10 is 26 As a binary number it's 11010 That binary number back to base-10 is 26.

Explanation / Answer

package sample;
import java.util.Scanner;
public class hw1 {
public static void main(String[] args) {
Scanner s=new Scanner(System.in);
System.out.println("Enter a string holding a hexadecimal integer less than 256 : ");
String hex=s.nextLine();
int n=hexaToDecimal(hex);
System.out.println(" Decimal equivalent base-10 is : "+n);
System.out.println(" Binary equivalent base-2 is : "+Integer.toBinaryString(n));
System.out.println(" Decimal equivalent base-10 is : "+binToDec(Integer.parseInt(Integer.toBinaryString(n))));
}
public static int hexaToDecimal(String s)
{
String digits = "0123456789ABCDEF";
s = s.toUpperCase();
int val = 0;
for (int i = 0; i < s.length(); i++)
{
char c = s.charAt(i);
int d = digits.indexOf(c);
val = 16*val + d;
}
return val;
}
public static int binToDec(Integer n)
{
   int binnum, decnum=0, i=1, rem;
  
       binnum=n.intValue();
while(binnum != 0)
{
rem = binnum%10;
decnum = decnum + rem*i;
i = i*2;
binnum = binnum/10;
}
      
return decnum;

}
}

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