Two computers are connected together through their serial ports and Hyper-termin

Question

Two computers are connected together through their serial ports and Hyper-terminal communication software system. The data communication settings between the two computers are as follows: data transmission speed (bps) = 9600 data bits = 8 Parity bit = even stop bit = 2 start bit = 1 What is the data transmission time in seconds, (the time that takes to complete the transmission of 38400 bytes and the extra bits). The number needs to be expressed in 2 decimal places; for example, 25.00 or 40.15. Please do not write anything else after the number.

Explanation / Answer

Frame size for this serial communication is =

startbit+data bits+paritybit+stopbit= 1 + 8 + 1 + 2 = 12 bits

The frame size is of 12 bits.

Data transmission speed = file size * bits per transmission/bit_rate(or baud rate)

= 38400*12/9600

=460800/9600

= 48.00

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