In the language c using the isspace() function: Write a program to count the num

Question

In the language c using the isspace() function: Write a program to count the number of words, lines, and characters in its input. A word is any sequence of non-white-space characters.

Have your program continue until end-of-file. Make sure that your program works for the case of several white space characters in a row. The character count should also include white space characters.

Test the program by using the statement below

             You're traveling through

               another dimension;

              a dimension not only

              of sight and sound,

               but of mind.

Explanation / Answer

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
   char ch, file_name[25];
   FILE *fp;
   int no_of_characters=0;
   int no_of_lines=0;
   int no_of_words=0;
    char check;  
   printf("Enter the path/name of file you wish to see ");
   gets(file_name);
   fp = fopen(filename,"r"); // read mode

   if( fp == NULL )
   {
      perror("Error while opening the file. ");
      exit(EXIT_FAILURE);
   }
    if( ( ch = fgetc(fp) ) != EOF ){
       ch=fgetc(fp);
       no_of_characters++;
       check=ch;
}
   while( ( ch = fgetc(fp) ) != EOF ){
      if(!(check==' ') && !(check==' '))
        no_of_characters++;
    
      if(isspace(ch) && !(check==' ') && !(check==' ')){
          no_of_words++;
      }
    
      if(ch == ' '){
          no_of_lines++;
      }
      check=ch;
   }

   if(no_of_characters > 0){
       no_of_words++;
   }

if(no_of_characters > 0 && no_of_lines < 1){
       no_of_lines++;
   }
   fclose(fp);

   printf("The no of characters are : %d ",no_of_characters);
   printf("the no of the words are : %d ",no_of_words);
   printf("The no of lines are : %d ",no_of_lines);

   return 0;
}

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