**If answer is clear correct and readable I will provide positive feedback ** Co
ID: 381561 • Letter: #
Question
**If answer is clear correct and readable I will provide positive feedback **Consider a single-server queuing syatem. If the arrival rate is 8080 units per hour, and each customer takes 40 seconds on average to be served, what is the average time in the system to include service (answer in minutes to 2 decimal places) **If answer is clear correct and readable I will provide positive feedback **
Consider a single-server queuing syatem. If the arrival rate is 8080 units per hour, and each customer takes 40 seconds on average to be served, what is the average time in the system to include service (answer in minutes to 2 decimal places) **If answer is clear correct and readable I will provide positive feedback **
Consider a single-server queuing syatem. If the arrival rate is 8080 units per hour, and each customer takes 40 seconds on average to be served, what is the average time in the system to include service (answer in minutes to 2 decimal places)
Explanation / Answer
Consider a Single-server queuing system. If the arrival rate is 80 units per hour, and each customer takes 40 seconds on average to be served, what is the average time in the system to include service (answer in minutes to 2 decimal places)
We have following information,
Customers arrive at a rate of 80 per hour therefore Arrival rate = 80 customers per hour
Service time is 40 seconds per customer therefore, in one hour number of customers served = one hour / 40 second = 60 * 60 second / 40 = 90 customers
Therefore, Service rate µ = 90 customer per hour
The average the average time in the system to include service W = Wq + 1/µ
Where, Wq = /µ * (µ - ) = 80 / 90 * (90 -80) = 80/ 90 * 10 = 0.0888 hour or 5.33 minutes
Therefore,
The average time customers spend in the system W = Wq + 1/µ
W = 0.0888 + 1/90
= 0.01 hours or 6 minutes
Therefore average time the system to include service time is 6.00 minutes.
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