What is the following C++ code; int myfunction( int arr[], int a, int b){ int t;

Question

What is the following C++ code;

int myfunction( int arr[], int a, int b){

int t;

if ((a>b)|| (b<0)||(a<0)) {return -1;}

while (a

             t=arr[a]

             arr[a] = arr[b];

arr[b] = t;

a++;b--;                 }

   return 0;          }

int main(){

            int x[10]= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

            myfunction(x, 5, 7);

            for (int i=0; i<0; i++){

                  cout << x[i] << “ ”;

            }

            return 0;

}

a. 1 2 3 4 5 6 7 8 9 10

b. 10 9 8 7 6 5 4 3 2 1

c. 1 2 3 4 5 8 7 6 9 10

d. 1 3 5 7 9 2 4 6 8 10

Note : Please provide a solution

Explanation / Answer

i have rectified the mistakes of your code as shown below:

#include <iostream>
using namespace std;

int myfunction( int arr[], int a, int b){
int t;
if ((a>b)|| (b<0)||(a<0))
return -1;
while (a){
t=arr[a];
arr[a] = arr[b];
arr[b] = t;
a++;b--;
}
return 0;   
}

int main() {
int x[10]= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
myfunction(x, 5, 7);
for (int i=0; i<0; i++){
cout << x[i] <<" ";
}
   return 0;
}

op: 1 2 3 4 56 7 8 9 10

starting from the main function, an array x of 10 values are considered. then myfunction is called which passes value of arr= x, a= 5, b= 7. in myfunction it checks the if condition. since (5>7)|| (7<0)||(5<0) is false it goes back to the main function and enters for loop and hence prints the input values.

similarly for other input values,displays the input values as an output.

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