What is the following for the Molecule: N2O4 Molecular geometry (lst Nitrogen) I

Question

What is the following for the Molecule:   N2O4

Molecular geometry (lst Nitrogen)

Ideal bond angles (lst Nitrogen)

Molecular geometry (2nd Nitrogen)

Ideal bond angles (2nd Nitrogen)

Are polar bonds present? (Indicate on Lewis dot structure.)

Is there an overall dipole?

Octet rule violator and how?

What is the following for the Molecule: H2SO4

Molecular geometry (Sulfur)

Ideal bond angles (Sulfur)

Molecular geometry (lst Oxygen)

Ideal bond angles (lst Oxygen) Molecular geometry (2nd Oxygen)

Ideal bond angles (2nd Oxygen)

Are polar bonds present? (Indicate on Lewis dot structure.)

Is there an overall dipole?

Octet rule violator and how?

Explanation / Answer

a) N2O4   

both nitrogens are sp2 hybridised and planar trigonal. the ideal bond angle for this geometry is 120. It is regarded as two NO2 groups bonded together.

The molecule is not polar and the bonds between N-O are polar.

O=N (O) -N(O)=O

NOt octet rule violater , as each nitrogen has octet completed.

b) In H2SO4 , sulfur is sp3 hybridised and the geometry is tetrahedral . It has two double bonds with two oxygens and two-OH bonds.

ideal bongles are 109.5 .

Bothe double bonded oxygens are sp2 hybridised with ideal bond angles of 120.

Yes. The bonds between o and H and s and O are polar.

overall dipole .

violates octet rule as S has 6 bonds and has 12 valence electrons in it.

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