What will the value of c be as a result of executing the following code? Int a =

Question

What will the value of c be as a result of executing the following code?

Int a = 4, b = 22;

Double c;

c = (double) ( b / a ) – b % a;

3.0

3.5

What will the value of k be as a result of executing the following code?

int i = 15;

int j = 15;

Double k = 36.0;

k = i + j % 2 + k / (i – 5);

3.6

19.6

What is the result of the following expression?

21 / 2 + 22 % 5 * 3

16

22

23

What would the following code output?

double checking = 50.0;

int m = 2; do{

m++;

    checking = checking - 3 * m;

} while (checking >= 30;

System.out.println(m);

A.4

B.6

C.7

What does the following code output?

int price = 10, base = 15;

if (price > base)

System.out.println("Buy");

else if (price < 12)

System.out.println("Sell");

else

System.out.println("Unknown");

Buy

Sell

Explanation / Answer

1. What will the value of c be as a result of executing the following code?

int a = 4, b = 22;

double c;

c = (double) (b / a) – b % a;

3.0

3.5

Answer: 3.0

Explanation: First b / a is evaluated, 22 / 4 is 5 as both b and a are integers, now 5 is converted to double which is 5.0

Now b % a is evaluated, which is 22 % 4, the remainder is 2

Now c will be 5.0 – 2 which is 3.0

2. What will the value of k be as a result of executing the following code?

int i = 15;

int j = 15;

double k = 36.0;

k = i + j % 2 + k / (i – 5);

3.6

19.6

Answer: 19.6

Explanation: First (i-5) is evaluated, which is 15-5 = 10

Now k / (i-5) is evaluated, 36.0 / 10 = 3.6

Now j % 2 is evaluated which is 15 % 2 = 1 (remainder after 15 divided by 2)

Now finally i + j % 2 + k / (i – 5) = 15 + 1 + 3.6 = 19.6

3. What is the result of the following expression?

21 / 2 + 22 % 5 * 3

16

22

23

Answer: 16

Explanation: Expression evaluations follow BODMAS rule

As per BODMAS rule 21 / 2 is first evaluated which is 10

Next 22 % 5 is evaluated which is 2

Now 22 % 5 * 3 is evaluated which is 2 * 3 = 6

Finally the complete expression is evaluated as 10 + 6 = 16

4. What would the following code output?

double checking = 50.0;

int m = 2; do{

m++;

    checking = checking - 3 * m;

} while (checking >= 30);

System.out.println(m);

A.4

B.6

C.7

Answer: A. 4

Explanation: In the given we have checking = 50.0 and m = 2

Next we have a do while loop which iterates until checking > =30

Iteration 1: m is incremented by 1, now m will be 3

Next checking = checking – 3* m = 50.0 – 9

checking = 41

Now the condition checking > =30 is checked, this is true and the loop continues

Iteration 2: m is incremented by 1, now m will be 4

Next checking = checking – 3* m = 41 – 12

checking = 29

Now the condition checking > =30 is checked, this is false and the loop terminates

Finally we are printing m, as the value of m is now 4, 4 is printed

5. What does the following code output?

int price = 10, base = 15;

if (price > base)

System.out.println("Buy");

else if (price < 12)

System.out.println("Sell");

else

System.out.println("Unknown");

Buy

Sell

Answer: Sell

Explanation: We have price = 10 and base = 15

Next we have if condition here price > base is checked, which is 10 > 15 which is false, hence it goes to the else part, here again we have one more if condition if(price < 12) this is true

And the statements in the else part are executed and prints Sell the rest of the statements are discarded.

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